MS - Kenneth Jonassen vs Park Tae Sang WS - Wang Chen vs Mia Audina MD - Kim/Ha vs Lee/Yo WD - Ra/Lee vs Olsen/Jorgensen MX - Kim/Ra vs Kim/Lee My Guess: MS - Kenneth Jonassen WS - Wang Chen MD - Lee/Yo WD - Ra/Lee MX - Kim/Ra
don't remember having ever seen a match between Wang Chen and Mia. guts feeling is Wang Chen. chance for her to win a big tourney. Kim/Ha vs. Lee/Yoo. this match will tell us if Ha has recovered or not. normally, they will kill Lee/Yoo. but Lee/Yoo are in pretty good shape.
The only match in recent history that they played against each other was at Sudirman C this year? Wang bt. Mia 11-6, 11-8. Apparently, their lifetime matches are 6-4 in favor of Wang. Kwun, you were at SC this year, how could you not remember this? Regarding the Korean Open in general though, it is apparent that without Chinese competition at a major event, many unexpected players can enter semis and finals stage. If China had sent all their top players, then in MS there would be at max only 2 Koreans in quarter-finals instead of 4! Even 2 is very lucky as Korea only had 1 player remaining by quarter-final stage at Japan Open last week. So, most likely Korea's gonna sweep all 3 doubles. But in MS I think Kenny J can take Park Tae Sang in a close match.
Mia beat Wang Chen. WC didn;t play a good game but the 3rd set was pretty abysmal. Even the commentator said 'it's not the fact that she played badly. All plyaers have their bad days. It's that she showed no fighting spirit in the last game. Jonassen threw a wobbly in his 2nd game. He was cruising something like 14-5 in the 2nd game and then Park caught up to setting! Spare a little pity for Ann Jorgensen. The Koreans worked her around and really placed their smashes well.
Glad to see Jonassen finally winning one of the big tournaments! After these many years in top badminton, he's deserved it.
isn't that Wang Chen's style, always looks very laid back? i think Ra/Lee is revenging on the SC match they played. Olsen/Jorgensen hit may be 80% of all shots to Lee durign that match.