Just some sideline trivia: Correct me on the maths...... There are 163 racquets (or thereabouts on the review list) If we get a thread asking for a comparison on xx racquet vs zz racquet, there are 163! possible combinations. Multiply that by four for the replies. What's the answer? Scroll down. A full up message board. BTW, do u think IBF is still tracking us?
Cheung, There are more than 163 possible combinations under your example. There would be 162 possible pairings with racquet #1 alone. We do not take kindly to your sort of insinuated critcisms. Accordingly, we will be declaring your equipment as non-conforming at the next tournament you enter. Sincerely, The International Badminton Federation
I think it would come out to more than that because a given racquet may have different versions such as Ti-10 long and Ti-10 regular, or Cab 10 or Cab 10 Tour. You get the point.
Don, it would be less than 163x162. For each number down the list, you would have one fewer new combination than the last racquet. Thus, for racquet #10, there would be 152 new combinations and for racquet #162, there would be only one different match. There's a button on an advanced calculator that will perform this calculation, but I haven't done this since high school and have forgotten which math function this is.
Kwun, not if you assume that the comparison of #1 vs. #163 is the same as the comparison of #163 vs. #1. Badminton is offering us not only physical exercise but intellectual exercise too (physics for string tension arguments, math for racquet comparison calculations, etc...)
I dug up the old arithmetic series formula and found that by eliminating a duplicate i.e. 1 vs 2 or 2 vs 1, my calculations brings it to be 13203 distinct comparisons.
Which, coincidentally or perhaps not, is one half of 163x162. I guess we better get to work on those comparisons. Perhaps Kwun could write a grant proposal and fund us all as his research assistants.
Brett. Brett, you're right, i did 163 P 2 instead of 163 C 2. it has been a while since i did this... need to dig out those old math textbooks!! anyway, this is what i remember: a C b = a! / ( (a-b)! * b! ) which in our case, is 163*162/2 and a P b = a! / (a-b)! which is 163*162
kwun.. you're still off the ball. It's a permutation not a combination. Order does matter, so you simpley divide by 2 to elimate the duplicate.
Don. we may be talking about the same thing and i may not be clear on my last msg. i was saying that we don't want to have permutation/ordering, thus we want 163 C 2 instead of 163 P 2. and 163 C 2 does include the divide by 2.. we don't differentiate "compare a Ti10 with MP100" and "compare a MP100 with Ti10", am i correct?
